b^2-3b+20=0

Solution for b^2-3b+20=0 equation:

Simplifying
b2 + -3b + 20 = 0

Reorder the terms:
20 + -3b + b2 = 0

Solving
20 + -3b + b2 = 0

Solving for variable 'b'.

Begin completing the square.

Move the constant term to the right:

Add '-20' to each side of the equation.
20 + -3b + -20 + b2 = 0 + -20

Reorder the terms:
20 + -20 + -3b + b2 = 0 + -20

Combine like terms: 20 + -20 = 0
0 + -3b + b2 = 0 + -20
-3b + b2 = 0 + -20

Combine like terms: 0 + -20 = -20
-3b + b2 = -20

The b term is -3b.  Take half its coefficient (-1.5).
Square it (2.25) and add it to both sides.

Add '2.25' to each side of the equation.
-3b + 2.25 + b2 = -20 + 2.25

Reorder the terms:
2.25 + -3b + b2 = -20 + 2.25

Combine like terms: -20 + 2.25 = -17.75
2.25 + -3b + b2 = -17.75

Factor a perfect square on the left side:
(b + -1.5)(b + -1.5) = -17.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.